What is the hybridisation of each carbon in $H_2C = C = CH_2$?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The carbon atoms $1$ and $3$ are $sp^2$ hybridized because each is bonded to three atoms (two $H$ atoms and one $C$ atom) and participates in one double bond.
The central carbon atom $(C_2)$ is $sp$-hybridized because it is bonded to two carbon atoms via two double bonds.
In the structure of allene $(H_2C=C=CH_2)$,the two $\pi$ bonds are perpendicular to each other. The $2p_y$ and $2p_z$ orbitals of the central carbon atom $(C_2)$ are involved in the formation of $\pi$ bonds with the adjacent carbon atoms,leaving only the $2s$ and one $2p$ orbital for hybridization,resulting in $sp$ hybridization for $C_2$.

Explore More

Similar Questions

Fill in the blanks:
$(i)$ Based on the type of overlapping,covalent bonds are classified into ........ and .......... .
$(ii)$ The bond formation involving hybrid orbitals is called ............. .
$(iii)$ The type of hybridization observed in the $C_2H_6$ molecule is ........... .
$(iv)$ The type of hybridization observed in the $BrF_5$ complex is ............... .

Observe the following reactions. Identify the reaction in which the hybridisation of the underlined atom is changed.

Hybridisation states of $C$ in $CH_3^+$ and $CH_4$ are

Which of the following molecular geometries is not produced by $sp^3$ hybridisation?

What are the hybridization type and molecular shape of the central atom in $BrF_5$,respectively?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo