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(C) The reaction of $HI$ with $3,3$-dimethyl-$1$-butene $(CH_3-C(CH_3)_2-CH=CH_2)$ proceeds via a carbocation intermediate.First,protonation of the al

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$CH_3-CI(CH_3)-CH(CH_3)-CH_3$

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(C) The reaction of $HI$ with $3,3$-dimethyl-$1$-butene $(CH_3-C(CH_3)_2-CH=CH_2)$ proceeds via a carbocation intermediate.First,protonation of the alkene forms a secondary carbocation: $CH_3-C(CH_3)_2-C^+H-CH_3$.To increase stability,a $1,2$-methyl shift occurs from the adjacent quaternary carbon,resulting in a more stable tertiary carbocation: $CH_3-C^+(CH_3)-CH(CH_3)-CH_3$.Finally,the nucleophilic attack of the iodide ion $(I^-)$ on this tertiary carbocation yields the major product,$2$-iodo-$2,3$-dimethylbutane $(CH_3-CI(CH_3)-CH(CH_3)-CH_3)$.

What is the major product formed by the reaction of $HI$ with $CH_3-C(CH_3)_2-CH=CH_2$?

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