What is the molar mass of the third homologue | vedclass

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(C) The general formula for the alkane series is $C_nH_{2n+2}$.For the first homologue $(n=1)$,the formula is $CH_4$ (methane).For the second homologu

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$44 \ g \ mol^{-1}$

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(C) The general formula for the alkane series is $C_nH_{2n+2}$.For the first homologue $(n=1)$,the formula is $CH_4$ (methane).For the second homologue $(n=2)$,the formula is $C_2H_6$ (ethane).For the third homologue $(n=3)$,the formula is $C_3H_8$ (propane).The molar mass of $C_3H_8$ is calculated as:$M = (3 	imes 12.01) + (8 	imes 1.008) \approx 36 + 8 = 44 \ g \ mol^{-1}$.

What is the molar mass of the third homologue of the alkane series?

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