What is the nature of the image formed by an | vedclass

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(C) Given: Focal length $(f)$ = $-20 	ext{ cm}$ (for a concave mirror),Object distance $(u)$ = $-10 	ext{ cm}$.Using the mirror formula: $\frac{1}{f

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Virtual and magnified

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(C) Given: Focal length $(f)$ = $-20 	ext{ cm}$ (for a concave mirror),Object distance $(u)$ = $-10 	ext{ cm}$.Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{-20} = \frac{1}{v} + \frac{1}{-10}$.Rearranging: $\frac{1}{v} = \frac{1}{10} - \frac{1}{20} = \frac{2-1}{20} = \frac{1}{20}$.So,$v = +20 	ext{ cm}$.Since the image distance $(v)$ is positive,the image is formed behind the mirror,which means it is virtual.Magnification $(m)$ = $-\frac{v}{u} = -(\frac{20}{-10}) = +2$.Since $m$ is positive and greater than $1$,the image is virtual and magnified.

What is the nature of the image formed by an object placed at a distance of $10 \text{ cm}$ in front of a concave mirror with a focal length of $20 \text{ cm}$?

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