What is the normality of an aqueous solution | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dissociation of $H_2SO_4$ is given by: $H_2SO_4 \rightarrow 2H^+ + SO_4^{2-}$.Given $pH = 1$,we know that $[H^+] = 10^{-pH} = 10^{-1} = 0.1 \

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(A) The dissociation of $H_2SO_4$ is given by: $H_2SO_4 ightarrow 2H^+ + SO_4^{2-}$.Given $pH = 1$,we know that $[H^+] = 10^{-pH} = 10^{-1} = 0.1 \ M$.Since $1 \ mol$ of $H_2SO_4$ produces $2 \ mol$ of $H^+$,the molarity $(M)$ of $H_2SO_4$ is $[H^+] / 2 = 0.1 / 2 = 0.05 \ M$.Normality $(N)$ is calculated as $Molarity 	imes n$-factor.For $H_2SO_4$,the $n$-factor is $2$.Therefore,$N = 0.05 	imes 2 = 0.1 \ N$.

What is the normality of an aqueous solution of $H_2SO_4$ having $pH = 1$ (in $N$)?

Similar Questions

The $pH$ of a $10^{-10} \ M \ NaOH$ solution is approximately......

The hydrogen ion concentration of a $10^{-8} \ M \ HCl$ aqueous solution at $298 \ K$ $(K_w = 10^{-14})$ is

What will be the $pH$ of a $10^{-8} \ M$ solution of $HCl$?

$40 \, mg$ of pure sodium hydroxide is dissolved in $10 \, L$ of distilled water. The $pH$ of the solution is

If $0.4 \ g$ of $NaOH$ is present in $1 \ L$ of solution,then the $pH$ of the solution is .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module