What is the number of sp^3 hybrid carbon atom | vedclass

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(C) The given molecule is $HO-CH_2-CH_2-CH_2-CH(CH_3)-CH(CH_3)_2$.Expanding the structure: $HO-CH_2-CH_2-CH_2-CH(CH_3)-CH(CH_3)_2$.All carbon atoms in

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Eight

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(C) The given molecule is $HO-CH_2-CH_2-CH_2-CH(CH_3)-CH(CH_3)_2$.Expanding the structure: $HO-CH_2-CH_2-CH_2-CH(CH_3)-CH(CH_3)_2$.All carbon atoms in this molecule are bonded to four other atoms via single bonds,meaning they are all $sp^3$ hybridized.Counting the carbon atoms: $3$ (from $(CH_2)_3$) + $1$ (from $CH$) + $1$ (from $CH_3$) + $1$ (from $CH$) + $2$ (from $(CH_3)_2$) = $8$ carbon atoms.Therefore,there are $8$ $sp^3$ hybridized carbon atoms.

What is the number of $sp^3$ hybrid carbon atoms in $HO(CH_2)_3CH(CH_3)CH(CH_3)_2$?

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