What is the number of electrons around sulfur in $H_2SO_4$ molecule?

  • A
    $4$
  • B
    $6$
  • C
    $10$
  • D
    $12$

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Similar Questions

Match List-$I$ with List-$II$ and select the correct answer:
List-$I$ (Molecule / Species) List-$II$
$(P)$ $NO_2$ (Unpaired electron in) $(1)$ Vacant $p$-orbital involved in hybridization
$(Q)$ $B_2H_6$ $(2)$ $sp^2$-orbital
$(R)$ $ClO_3$ (Unpaired electron in) $(3)$ $sp^3$-orbital
$(S)$ $CH_3^+$ $(4)$ $120^\circ$ Bond angle

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$X-O-X$ linkage is present in $[X = P/S/Cl/Mn]$:
$(a) P_2O_7^{4-}$
$(b) S_2O_5^{2-}$
$(c) S_2O_7^{2-}$
$(d) Cl_2O_7$
$(e) Mn_2O_7$
$(f) S_2O_8^{2-}$

The number of sigma $(\sigma)$ and pi $(\pi)$ bonds in peroxodisulphuric acid are, respectively:

The formal charges of $N_{(1)}$,$N_{(2)}$ and $O$ atoms in the structure shown below are respectively:
$:N_{(1)}=N_{(2)}=\ddot{O}:$

Arrange the bonds in order of increasing ionic character in the molecules: $LiF$,$K_2O$,$N_2$,$SO_2$,and $ClF_3$.

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