What is the number of electrons in bonding mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total number of electrons in an $F_2$ molecule is $18$ $(9 + 9)$.The molecular orbital configuration for $F_2$ is: $\sigma 1s^2, \sigma^* 1s^2

Vedclass · Accepted Answer

$10$ and $8$

Vedclass · Answer

(B) The total number of electrons in an $F_2$ molecule is $18$ $(9 + 9)$.The molecular orbital configuration for $F_2$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.Counting the electrons in bonding molecular orbitals (those without an asterisk): $2 (\sigma 1s) + 2 (\sigma 2s) + 2 (\sigma 2p_z) + 4 (\pi 2p_x, \pi 2p_y) = 10$.Counting the electrons in antibonding molecular orbitals (those with an asterisk): $2 (\sigma^* 1s) + 2 (\sigma^* 2s) + 4 (\pi^* 2p_x, \pi^* 2p_y) = 8$.Therefore,the number of electrons in bonding and antibonding molecular orbitals are $10$ and $8$ respectively.

What is the number of electrons in bonding molecular orbitals and antibonding molecular orbitals respectively in $F_2$ molecule?

Similar Questions

Which of the following is paramagnetic as well as it has a fractional bond order?

Which of the following species is paramagnetic?

According to molecular orbital theory,antibonding molecular orbitals of $O_2$ contain

Two homo-diatomic molecules $X_2$ and $Y_2$ have the same bond order. Then,select the $CORRECT$ statement.

What is the number of unpaired electron$(s)$ in the highest occupied molecular orbital $(HOMO)$ of the following species: $N_2$,$N_2^{+}$,$O_2$,$O_2^{+}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module