What is the number of moles of H atoms requir | vedclass

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(B) The reduction of acetamide $(CH_3CONH_2)$ to ethylamine $(CH_3CH_2NH_2)$ using a strong reducing agent like $LiAlH_4$ or $Na/C_2H_5OH$ is represen

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The reduction of acetamide $(CH_3CONH_2)$ to ethylamine $(CH_3CH_2NH_2)$ using a strong reducing agent like $LiAlH_4$ or $Na/C_2H_5OH$ is represented by the following chemical equation:$CH_3CONH_2 + 4[H] \xrightarrow{LiAlH_4/ether} CH_3CH_2NH_2 + H_2O$From the stoichiometry of the reaction,it is clear that $4$ moles of nascent hydrogen $([H])$ are required to reduce $1$ mole of acetamide to $1$ mole of ethylamine.Therefore,the correct option is $B$.

What is the number of moles of $H$ atoms required to prepare one mole of ethylamine from one mole of acetamide?

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