What is the number of moles present in 1 m^3 | vedclass

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(C) At $STP$ (Standard Temperature and Pressure),the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$ (using the current $IUPAC$ standard of $1 \

Vedclass · Accepted Answer

$44.6$

Vedclass · Answer

(C) At $STP$ (Standard Temperature and Pressure),the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$ (using the current $IUPAC$ standard of $1 \ bar$ pressure).Given volume $V = 1 \ m^3 = 1000 \ L$.The number of moles $n$ is calculated as:$n = \frac{V}{V_m} = \frac{1000 \ L}{22.7 \ L \ mol^{-1}} \approx 44.05 \ mol$.If using the older $STP$ definition ($1 \ atm$ pressure),the molar volume is $22.4 \ L \ mol^{-1}$.$n = \frac{1000 \ L}{22.4 \ L \ mol^{-1}} \approx 44.64 \ mol$.Rounding to the nearest value provided in the options,the correct answer is $44.6$.

What is the number of moles present in $1 \ m^3$ of any gas at $STP$?

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