(D) Let the oxidation number of $Cr$ be $x$. For $K_{2}Cr_{2}O_{7}$,the sum of oxidation numbers of all atoms is $0$. $(+1 \times 2) + (x \times 2) +

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(D) Let the oxidation number of $Cr$ be $x$. For $K_{2}Cr_{2}O_{7}$,the sum of oxidation numbers of all atoms is $0$. $(+1 \times 2) + (x \times 2) + (-2 \times 7) = 0$ $2 + 2x - 14 = 0$ $2x - 12 = 0$ $2x = 12$ $x = +6$ Therefore,the oxidation number of $Cr$ is $+6$.