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What is the difference in the oxidation number of nitrogen when nitric acid is converted into nitrous oxide?
DifficultMHT CET 2026
View SolutionThe correct order of $N$ compounds in their decreasing order of oxidation states is:
MediumNEET 2018
View SolutionMatch the following compounds with their respective oxidation numbers of the central atom or specific element:
Compound Oxidation number $1$. $C_2H_6$ $a$. $+3$ $2$. $H_2O_2$ $b$. $+6$ $3$. $LiAlH_4$ $c$. $-3$ $4$. $HO_2^-$ $d$. $-1$ $5$. $PbSO_4$ $e$. $+1$
| Compound | Oxidation number |
|---|---|
| $1$. $C_2H_6$ | $a$. $+3$ |
| $2$. $H_2O_2$ | $b$. $+6$ |
| $3$. $LiAlH_4$ | $c$. $-3$ |
| $4$. $HO_2^-$ | $d$. $-1$ |
| $5$. $PbSO_4$ | $e$. $+1$ |
Medium
View SolutionMatch the items in Column-$I$ with relevant items in Column-$II$.
Column-$I$ Column-$II$ $A$. Positively charged ion $1$. $+7$ $B$. Oxidation number of all neutral atoms $2$. $-1$ $C$. Oxidation number of hydrogen $(H^+)$ $3$. $+1$ $D$. Oxidation number of fluorine in $NaF$ $4$. $0$ $E$. Negatively charged ion $5$. Cation $6$. Anion
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Positively charged ion | $1$. $+7$ |
| $B$. Oxidation number of all neutral atoms | $2$. $-1$ |
| $C$. Oxidation number of hydrogen $(H^+)$ | $3$. $+1$ |
| $D$. Oxidation number of fluorine in $NaF$ | $4$. $0$ |
| $E$. Negatively charged ion | $5$. Cation |
| $6$. Anion |
Medium
View SolutionThe oxidation number of sulphur in $S_2O_3^{2-}$ is:
Easy
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