What is the oxidation number of iron in the c | vedclass

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(A) The compound $[Fe(H_2O)_5(NO)]SO_4$ dissociates into $[Fe(H_2O)_5(NO)]^{2+}$ and $SO_4^{2-}$ ions.In the complex ion $[Fe(H_2O)_5(NO)]^{2+}$,the l

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$+1$

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(A) The compound $[Fe(H_2O)_5(NO)]SO_4$ dissociates into $[Fe(H_2O)_5(NO)]^{2+}$ and $SO_4^{2-}$ ions.In the complex ion $[Fe(H_2O)_5(NO)]^{2+}$,the ligand $H_2O$ is neutral (oxidation state $0$).The ligand $NO$ in the brown ring complex is considered to be in the $NO^+$ form (nitrosonium ion),which has an oxidation state of $+1$.Let the oxidation state of $Fe$ be $x$.$x + 5(0) + 1 = +2$$x = +2 - 1 = +1$.Therefore,the oxidation state of $Fe$ is $+1$.

What is the oxidation number of iron in the compound $[Fe(H_2O)_5(NO)]SO_4$?

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