What is the pressure of hydrogen in a cylinde | vedclass

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Question

(A) The pressure $P$ of an ideal gas is related to its total translational kinetic energy $E$ and volume $V$ by the formula: $P = \frac{2}{3} \frac{E}

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$5 	imes 10^5 	ext{ Nm}^{-2}$

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(A) The pressure $P$ of an ideal gas is related to its total translational kinetic energy $E$ and volume $V$ by the formula: $P = \frac{2}{3} \frac{E}{V}$.Given,$E = 7.5 	imes 10^3 	ext{ J}$ and $V = 10 	ext{ litre} = 10 	imes 10^{-3} 	ext{ m}^3 = 10^{-2} 	ext{ m}^3$.Substituting the values into the formula:$P = \frac{2}{3} 	imes \frac{7.5 	imes 10^3}{10^{-2}}$$P = \frac{2}{3} 	imes 7.5 	imes 10^5$$P = 5 	imes 10^5 	ext{ N/m}^2$.

What is the pressure of hydrogen in a cylinder of volume $10 \text{ litre}$ if its total energy of translation is $7.5 \times 10^3 \text{ J}$?

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