What is the probability of getting a sum 9 fr | vedclass

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(C) The total number of possible outcomes when a dice is thrown twice is $6 	imes 6 = 36$.The favorable outcomes to get a sum of $9$ when a dice is t

Vedclass · Accepted Answer

$\frac{1}{9}$

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(C) The total number of possible outcomes when a dice is thrown twice is $6 	imes 6 = 36$.The favorable outcomes to get a sum of $9$ when a dice is thrown twice are:$(3, 6), (4, 5), (5, 4), (6, 3)$.There are $4$ such favorable outcomes.Let $E$ be the event of getting a sum of $9$.Therefore,the probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of possible outcomes}} = \frac{4}{36} = \frac{1}{9}$.

What is the probability of getting a sum $9$ from two throws of a dice?

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