What is the product in the above reaction?

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(D) The reaction of $1$-bromo-$4$-chlorobenzene with $Mg$ in diethyl ether forms a di-Grignard reagent, $ClMg-C_6H_4-MgBr$. When this di-Grignard reag

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$1,4-$benzenedimethanol

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(D) The reaction of $1$-bromo-$4$-chlorobenzene with $Mg$ in diethyl ether forms a di-Grignard reagent, $ClMg-C_6H_4-MgBr$. When this di-Grignard reagent reacts with $2$ equivalents of formaldehyde $(CH_2O)$, it undergoes nucleophilic addition at both the $ClMg-$ and $-MgBr$ sites. Subsequent acidic hydrolysis $(H_3O^+)$ converts both $-CH_2OMgX$ groups into $-CH_2OH$ groups. Thus, the final product is $1,4$-benzenedimethanol (also known as $p$-xylylene glycol).

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