What is the product obtained in the reaction?
$CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) H_3O^{+}]{(i) LiAlH_4} \text{product}$

  • A
    $CH_3-CH=CH-CH_2-CH_2-OH$
  • B
    $CH_3-CH=CH-CH_2-COOH$
  • C
    $CH_3-CH_2-CH_2-CH_2-CHO$
  • D
    $CH_3-CH_2-CH_2-CH_2-CH_3$

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