What is the proportion of $s$-character in $sp^3$,$sp^2$,and $sp$ hybrid orbitals? What is the order of electronegativity in it?

(N/A) The $s$-character in hybrid orbitals is calculated as follows:
$sp^3$: $1/4 = 25 \%$,$sp^2$: $1/3 = 33.3 \%$,$sp$: $1/2 = 50 \%$.
Electronegativity is directly proportional to the $s$-character because $s$-orbitals are closer to the nucleus.
Therefore,the order of electronegativity is $sp > sp^2 > sp^3$.

Hybrid Orbital	$s$-character
$sp^3$	$25 \%$
$sp^2$	$33.3 \%$
$sp$	$50 \%$