What is the reading in the AC ammeter for the | vedclass

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(C) The circuit consists of an inductor with inductive reactance $X_L = 24 \ \Omega$ and a capacitor with capacitive reactance $X_C = 48 \ \Omega$ con

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$5$

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(C) The circuit consists of an inductor with inductive reactance $X_L = 24 \ \Omega$ and a capacitor with capacitive reactance $X_C = 48 \ \Omega$ connected in parallel to an $AC$ source of $V = 240 \ V$.The current through the inductor is $I_L = \frac{V}{X_L} = \frac{240}{24} = 10 \ A$.The current through the capacitor is $I_C = \frac{V}{X_C} = \frac{240}{48} = 5 \ A$.In a parallel $LC$ circuit,the currents $I_L$ and $I_C$ are $180^{\circ}$ out of phase. Therefore,the total current $I$ measured by the ammeter is the magnitude of the difference between the two currents:$I = |I_L - I_C| = |10 \ A - 5 \ A| = 5 \ A$.

What is the reading in the $AC$ ammeter for the $AC$ circuit shown in the figure?

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