What is the value of spin-only magnetic momen | vedclass

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(C) The atomic number of $Cu$ is $29$. The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$, the electronic configuration is $[A

Vedclass · Accepted Answer

$1.73$

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(C) The atomic number of $Cu$ is $29$. The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$, the electronic configuration is $[Ar] 3d^9$. This means there is $1$ unpaired electron in the $3d$ orbital $(n = 1)$. The spin-only magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$. Substituting $n = 1$, we get $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.

What is the value of spin-only magnetic moment for $Cu^{2+}$ in $BM$?

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