What is the value of the slope in the Freundlich adsorption isotherm plot of $\log \frac{x}{m}$ against $\log C$?

Plot of $\log \left( \frac{x}{m} \right)$ against $\log P$ is a straight line inclined at an angle of $45^{\circ}$. When the pressure is $0.5 \ atm$ and Freundlich parameter $(K)$ is $10$,then the amount of solute adsorbed per gram of adsorbent is .......... $g$ $(\log 5 = 0.699)$.

Adsorption of a gas follows the Freundlich adsorption isotherm. In the given plot,$x$ is the mass of gas adsorbed on mass $m$ of the adsorbent at pressure $p$. $\frac{x}{m}$ is proportional to:

Which of the following is true for spontaneous adsorption?

Which of the following statements is $NOT$ applicable to chemisorption?

When $\left( \frac{m}{x} \right)$ is plotted against $\frac{1}{p}$ for the equation $\frac{x}{m} = \frac{ap}{1 + bp}$,we get a straight line. What are the slope and intercept of this line?