What is the voltage gain in a common emitter amplifier,where input resistance is $3 \, \Omega$ and load resistance is $24 \, \Omega$,and the current gain $\beta = 0.6$?

The output characteristics of a transistor in common emitter $(CE)$ mode is the graph obtained by plotting

In the shown common emitter amplifier circuit,$\beta = 80$ and $V_{BE} = 0.7\,V$. The value of $R_C$ is:

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$ and $2 \%$ of electrons recombine with holes in the base. The current ratios $\alpha$ and $\beta$ of the transistor are respectively (nearly):

In a common emitter transistor amplifier, an input signal of $10 \ mV$ is applied. Due to this signal, the change in base current is $50 \ \mu A$ and the corresponding change in collector current is $5 \ mA$. If the load resistance in the collector-emitter circuit is $5 \ k\Omega$, the change in output voltage will be ..... $V$.

In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of