What is the work done when a gas is compresse | vedclass

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(D) The formula for work done during compression is $W = -P_{ext} \Delta V = -P_{ext}(V_2 - V_1)$.Given $P_{ext} = 4.05 \ bar$,$V_1 = 2.5 	imes 10^{-

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$4860$

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(D) The formula for work done during compression is $W = -P_{ext} \Delta V = -P_{ext}(V_2 - V_1)$.Given $P_{ext} = 4.05 \ bar$,$V_1 = 2.5 	imes 10^{-2} \ m^3$,and $V_2 = 1.3 	imes 10^{-2} \ m^3$.Substituting the values: $W = -4.05 \ bar 	imes (1.3 	imes 10^{-2} - 2.5 	imes 10^{-2}) \ m^3$.$W = -4.05 	imes (-1.2 	imes 10^{-2}) \ bar \cdot m^3 = 4.86 	imes 10^{-2} \ bar \cdot m^3$.Since $1 \ bar = 10^5 \ Pa$ and $1 \ Pa \cdot m^3 = 1 \ J$,we convert the units:$W = 4.86 	imes 10^{-2} 	imes 10^5 \ J = 4860 \ J$.

What is the work done when a gas is compressed from $2.5 \times 10^{-2} \ m^3$ to $1.3 \times 10^{-2} \ m^3$ at a constant external pressure of $4.05 \ bar$ (in $J$)?

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