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(B) To find the number that is divisible by $7, 11,$ and $14$,we first need to find their Least Common Multiple $(LCM)$.Step $1$: Find $\operatorname{

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$36$

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(B) To find the number that is divisible by $7, 11,$ and $14$,we first need to find their Least Common Multiple $(LCM)$.Step $1$: Find $\operatorname{LCM}(7, 11, 14)$.$7 = 7 	imes 1$$11 = 11 	imes 1$$14 = 2 	imes 7$$\operatorname{LCM} = 2 	imes 7 	imes 11 = 154$.Step $2$: Divide $1812$ by $154$ to find the remainder.$1812 \div 154 = 11$ with a remainder.$154 	imes 11 = 1694$.$1812 - 1694 = 118$.So,the remainder is $118$.Step $3$: Calculate the value to be added.To make $1812$ divisible by $154$,we need to add the difference between the divisor $(154)$ and the remainder $(118)$.Value to be added $= 154 - 118 = 36$.

What is the least value that should be added to $1812$ to make it divisible by $7, 11,$ and $14$?

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