What type of geometry and magnetic nature is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The central metal ion is $Ni^{2+}$. The atomic number of $Ni$ is $28$,so its electronic configuration is $[Ar] 3d^8 4s^2$.$2$. In $[NiCl_4]^{

Vedclass · Accepted Answer

Tetrahedral,Paramagnetic

Vedclass · Answer

(C) $1$. The central metal ion is $Ni^{2+}$. The atomic number of $Ni$ is $28$,so its electronic configuration is $[Ar] 3d^8 4s^2$.$2$. In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$,so the configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$3$. $Cl^-$ is a weak field ligand,so it does not cause pairing of electrons in the $3d$ orbitals.$4$. The $Ni^{2+}$ ion undergoes $sp^3$ hybridization using one $4s$ and three $4p$ orbitals.$5$. This results in a tetrahedral geometry.$6$. Since there are two unpaired electrons in the $3d$ orbitals,the complex is paramagnetic.

What type of geometry and magnetic nature is present in the complex $[NiCl_4]^{2-}$?

Similar Questions

Observe the following complexes: $[Mn(CN)_6]^{3-}, [Fe(CN)_6]^{3-}, [Co(C_2O_4)_3]^{3-}, [MnCl_6]^{3-}, [Fe(CN)_6]^{4-}, [CoF_6]^{3-}$. From the above,the number of inner orbital complexes with paramagnetic nature is

The correct statement among the following is:

An octahedral complex is formed when hybrid orbitals of the following type are involved:

Which of the following complexes exhibits $dsp^2$ hybridization?

Triple degenerate $d-$ orbitals are exactly half-filled in

Vedclass Test Series

Exam Paper Generator

Online Exam Module