What type of hybridisation is present in the | vedclass

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(A) The alkaline hydrolysis of $1-$bromo$-1-$phenylethane proceeds via an $S_N1$ mechanism.In the first,rate-determining step,the leaving group (bromi

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$sp^2$

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(A) The alkaline hydrolysis of $1-$bromo$-1-$phenylethane proceeds via an $S_N1$ mechanism.In the first,rate-determining step,the leaving group (bromide ion) departs,resulting in the formation of a carbocation intermediate.The carbocation intermediate has a positively charged carbon atom bonded to three other groups (a methyl group,a phenyl group,and a hydrogen atom).Since the positively charged carbon is bonded to three atoms and has no lone pairs,it is $sp^2$ hybridized,resulting in a planar geometry.The reaction is as follows:$CH_3-CH(Ph)-Br \rightleftharpoons CH_3-CH^+(Ph) + Br^-$$CH_3-CH^+(Ph) + OH^- \rightarrow CH_3-CH(OH)-Ph$

What type of hybridisation is present in the carbocation formed during the alkaline hydrolysis of $1-$bromo$-1-$phenylethane?

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