What type of hybridization is involved in [Fe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $[Fe(CN)_6]^{3-}$,the central metal ion is $Fe^{3+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{3+}$ is $[Ar] 3d

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(A) In $[Fe(CN)_6]^{3-}$,the central metal ion is $Fe^{3+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$.Since $CN^-$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which hybridize to form $d^2sp^3$ hybrid orbitals.Thus,the hybridization is $d^2sp^3$.

What type of hybridization is involved in $[Fe(CN)_6]^{3-}$?

Similar Questions

Among $Ni(CO)_4, [Ni(CN)_4]^{2-}$ and $[NiCl_4]^{2-}$,which of the following statements is correct?

What is the hybridisation and shape of $Cr$ in chromyl chloride $(CrO_2Cl_2)$?

In aqueous solution,$[Co(H_2O)_6]^{2+} (X)$ reacts with molecular oxygen in the presence of excess liquor $NH_3$ to give a new complex $Y$. The number of unpaired electrons in $X$ and $Y$ are,respectively:

Which of the following complex ions does not contain any $d$-electrons in the central metal atom?

The number of unpaired electrons in the complex $[CoF_6]^{3-}$ is ...... . (Atomic number of $Co = 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module