What type of the graph log(x/m) vs log P is o | vedclass

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(A) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = kP^{1/n}$.Taking logarithm on both sides,we get $\log(\frac{x}{m}) = \l

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$A$ straight line with a positive slope

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(A) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = kP^{1/n}$.Taking logarithm on both sides,we get $\log(\frac{x}{m}) = \log k + \frac{1}{n} \log P$.This equation is of the form $y = mx + c$,where $y = \log(\frac{x}{m})$,$x = \log P$,slope $m = \frac{1}{n}$,and intercept $c = \log k$.Therefore,the graph of $\log(\frac{x}{m})$ vs $\log P$ is a straight line with a positive slope equal to $\frac{1}{n}$.

What type of the graph $\log(x/m)$ vs $\log P$ is obtained for the Freundlich adsorption isotherm?

Similar Questions

Which one of the following equations represents the Freundlich adsorption isotherm?

Distinguish between the meaning of the terms adsorption and absorption. Give one example of each.

The graph drawn between $\log \left(\frac{x}{m}\right)$ and $\log (p)$ is shown below with intercept $OA = 0.3010$. What is the value of $\left(\frac{x}{m}\right)$ at a pressure of $0.3 \ atm$ ? (Given: $\log 2 = 0.3010, \log 3 = 0.477$)

Which of the following represent the Freundlich adsorption isotherms?
Choose the correct answer from the options given below:

Under what conditions does the rate of physisorption increase?

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