What volume of ethyl alcohol and water must b | vedclass

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(A) Let the volume of ethyl alcohol be $x \, mL$.The formula for volume percentage is:$	ext{Concentration} = \frac{	ext{Volume of solute (ethyl alco

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$150 \, mL$ of ethyl alcohol and $100 \, mL$ of water

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(A) Let the volume of ethyl alcohol be $x \, mL$.The formula for volume percentage is:$	ext{Concentration} = \frac{	ext{Volume of solute (ethyl alcohol)}}{	ext{Total volume of solution}} 	imes 100$Given:Total volume of solution = $250 \, mL$Concentration = $60 \%$Substituting the values:$60 = \frac{x}{250} 	imes 100$$x = \frac{60 	imes 250}{100} = 150 \, mL$Therefore,the volume of ethyl alcohol required is $150 \, mL$.The volume of water required = Total volume - Volume of ethyl alcohol$= 250 \, mL - 150 \, mL = 100 \, mL$.Thus,$150 \, mL$ of ethyl alcohol and $100 \, mL$ of water must be mixed.

What volume of ethyl alcohol and water must be mixed together to prepare $250 \, mL$ of $60 \%$ by volume of alcohol in water?

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