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(A) Step $1$: Calculate the number of moles in $16\, g$ of sulphur.Atomic mass of sulphur $(S)$ = $32\, g/mol$.Moles of $S = \frac{	ext{Given mass}}{

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$11.5$

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(A) Step $1$: Calculate the number of moles in $16\, g$ of sulphur.Atomic mass of sulphur $(S)$ = $32\, g/mol$.Moles of $S = \frac{	ext{Given mass}}{	ext{Atomic mass}} = \frac{16\, g}{32\, g/mol} = 0.5\, mol$.Step $2$: Determine the number of atoms.Since $1\, mol$ of any element contains $6.022 	imes 10^{23}$ atoms (Avogadro's number),$0.5\, mol$ of $S$ contains $0.5 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{23}$ atoms.Step $3$: Calculate the mass of sodium $(Na)$ containing the same number of atoms.Atomic mass of sodium $(Na)$ = $23\, g/mol$.To have the same number of atoms $(3.011 	imes 10^{23})$,we need $0.5\, mol$ of sodium.Mass of $Na = 	ext{Moles} 	imes 	ext{Atomic mass} = 0.5\, mol 	imes 23\, g/mol = 11.5\, g$.Therefore,$11.5\, g$ of sodium contains the same number of atoms as $16\, g$ of sulphur.

What weight of sodium contains the same number of atoms as are present in $16\, g$ of sulphur (in $, g$)?

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