(A) The relationship between $pH$ and hydrogen ion concentration is given by the formula: $[H^{+}] = 10^{-pH}$.Given $pH = 4.58$,we have $[H^{+}] = 10

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(A) The relationship between $pH$ and hydrogen ion concentration is given by the formula: $[H^{+}] = 10^{-pH}$.Given $pH = 4.58$,we have $[H^{+}] = 10^{-4.58}$.To calculate this,we can write $10^{-4.58} = 10^{0.42 - 5} = 10^{0.42} \times 10^{-5}$.Since $10^{0.42} \approx 2.63$,the concentration is $[H^{+}] = 2.63 \times 10^{-5} \, mol \, L^{-1}$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Water hydrolysis and pH scale

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What will be the hydrogen ion concentration in moles $L^{-1}$ of a solution whose $pH$ is $4.58$?

A
$2.63 \times 10^{-5}$
B
$3.0 \times 10^{-5}$
C
$4.68$
D
None of these

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6-2.Equilibrium-II (Ionic Equilibrium)

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Water hydrolysis and pH scale

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What will be the hydrogen ion concentration in moles $L^{-1}$ of a solution whose $pH$ is $4.58$?

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