What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature $T$? ($k_{B}$ is Boltzmann constant)
- A$\frac{1}{2} k_{B} T$
- B$\frac{2}{3} k_{B} T$
- C$\frac{3}{2} k_{B} T$
- D$k_{B} T$
Explore More
Similar Questions
The ratio of the kinetic energy of a diatomic gas molecule at a high temperature to that at $NTP$ is:
The number of rotational degrees of freedom of a monatomic molecule is
At a certain temperature,the degrees of freedom per molecule for a gas is $8$. The gas performs $150 \; J$ of work when it expands under constant pressure. The amount of heat absorbed by the gas will be $..... \; J$.
The number of rotational degrees of freedom of a diatomic molecule is:
For a gas,$\gamma = 7/5$. The gas may probably be
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo