What will be the decreasing order of basic st | vedclass

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(B) The basic strength of a conjugate base is inversely proportional to the acidic strength of its corresponding acid.The order of acidic strength of

Vedclass · Accepted Answer

$RO^{-} > OH^{-} > CH_3COO^{-} > Cl^{-}$

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(B) The basic strength of a conjugate base is inversely proportional to the acidic strength of its corresponding acid.The order of acidic strength of the corresponding acids is:$HCl > CH_3COOH > H_2O > ROH$Since $HCl$ is the strongest acid,its conjugate base $Cl^{-}$ is the weakest base.Since $ROH$ (alcohol) is a weaker acid than $H_2O$,its conjugate base $RO^{-}$ is a stronger base than $OH^{-}$.Therefore,the decreasing order of basic strength is:$RO^{-} > OH^{-} > CH_3COO^{-} > Cl^{-}$

What will be the decreasing order of basic strength of the following conjugate bases?
$OH^{-}, RO^{-}, CH_3COO^{-}, Cl^{-}$

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What will be the decreasing order of basic strength of the following conjugate bases?$OH^{-}, RO^{-}, CH_3COO^{-}, Cl^{-}$