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(A) The reactant is $N$-phenylbenzamide (benzanilide).In this molecule,the nitrogen atom is attached to a phenyl ring and a carbonyl group $(C=O)$.The

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(A) The reactant is $N$-phenylbenzamide (benzanilide).In this molecule,the nitrogen atom is attached to a phenyl ring and a carbonyl group $(C=O)$.The lone pair on the nitrogen atom is involved in resonance with the carbonyl group,which reduces its ability to donate electron density to the attached phenyl ring.However,the $-NH-CO-C_6H_5$ group is still an ortho/para directing group because of the lone pair on the nitrogen atom.Among the two phenyl rings,the one attached directly to the nitrogen atom is more activated towards electrophilic aromatic substitution $(EAS)$ compared to the ring attached to the carbonyl group (which is deactivated by the electron-withdrawing carbonyl group).Therefore,the nitronium ion $(NO_2^+)$ will attack the more activated ring at the para position due to steric hindrance at the ortho position.The major product is $N$-($4$-nitrophenyl)benzamide.

What will be the major product in the following mononitration reaction?

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