What will be the molality of the solution con | vedclass

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(C) Given,mass of $HCl = 18.25 \ g$. Molar mass of $HCl = 36.5 \ g/mol$. Mass of water $= 500 \ g = 0.5 \ kg$. Number of moles of $HCl = \frac{	ext{M

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) Given,mass of $HCl = 18.25 \ g$. Molar mass of $HCl = 36.5 \ g/mol$. Mass of water $= 500 \ g = 0.5 \ kg$. Number of moles of $HCl = \frac{	ext{Mass of } HCl}{	ext{Molar mass of } HCl} = \frac{18.25}{36.5} = 0.5 \ mol$. Molality $= \frac{	ext{Number of moles of solute}}{	ext{Mass of solvent in } kg}$. Molality $= \frac{0.5 \ mol}{0.5 \ kg} = 1 \ m$. Hence,the molality of the solution is $1 \ m$,thus the correct option is $C$.

What will be the molality of the solution containing $18.25 \ g$ of $HCl$ gas in $500 \ g$ of water (in $m$)?

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