What will be the order of 1^{st} ionisation e | vedclass

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(A) The $1^{st}$ ionisation energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom.In a group of the pe

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$Li > Na > K$

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(A) The $1^{st}$ ionisation energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom.In a group of the periodic table,as we move from top to bottom,the atomic size increases and the valence electrons are further away from the nucleus,resulting in a decrease in ionisation energy.For the alkali metals (Group $1$),the order of ionisation energy is $Li > Na > K > Rb > Cs$.Therefore,the correct order for $Li$,$Na$,and $K$ is $Li > Na > K$.

What will be the order of $1^{st}$ ionisation energy for the alkali metals $Li$,$Na$,and $K$?

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