When CuSO_4 is added to a solution of ammonia | vedclass

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(B) When $CuSO_4$ is added to an aqueous ammonia solution,it forms a complex ion: $Cu^{2+} + 4NH_3 \rightarrow [Cu(NH_3)_4]^{2+}$.This reaction leads

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Freezing point is raised

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(B) When $CuSO_4$ is added to an aqueous ammonia solution,it forms a complex ion: $Cu^{2+} + 4NH_3 ightarrow [Cu(NH_3)_4]^{2+}$.This reaction leads to a decrease in the total number of solute particles in the solution.According to the colligative property formulas,$\Delta T_f = i 	imes K_f 	imes m$ and $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor.$A$ decrease in the number of particles results in a decrease in the van't Hoff factor $(i)$.Since the depression in freezing point $(\Delta T_f)$ and elevation in boiling point $(\Delta T_b)$ are directly proportional to $i$,both values decrease.$A$ decrease in $\Delta T_f$ means the freezing point of the solution increases (it gets closer to the freezing point of the pure solvent).$A$ decrease in $\Delta T_b$ means the boiling point of the solution decreases (it gets closer to the boiling point of the pure solvent).Therefore,the freezing point is raised.

When $CuSO_4$ is added to a solution of ammonia,what happens to the colligative properties of the solution?

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