When $B_2H_6$ reacts with excess $NH_3$ at a very high temperature $(> 200 \, ^\circ C)$,the product formed is:
- A$[BH_2(NH_3)_2]^+ [BH_4]^-$
- B$(BN)_x$
- C$B_3N_3H_6$
- DNone
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