When H_2SO_4 reacts with PCl_5,the obtained p | vedclass

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Question

(D) The reaction between sulfuric acid $(H_2SO_4)$ and phosphorus pentachloride $(PCl_5)$ proceeds as follows: $H_2SO_4 + 2PCl_5 \rightarrow SO_2Cl_2

Vedclass · Accepted Answer

All of these

Vedclass · Answer

(D) The reaction between sulfuric acid $(H_2SO_4)$ and phosphorus pentachloride $(PCl_5)$ proceeds as follows: $H_2SO_4 + 2PCl_5 \rightarrow SO_2Cl_2 + 2POCl_3 + 2HCl$ As shown in the balanced chemical equation,the products formed are sulfuryl chloride $(SO_2Cl_2)$,phosphoryl chloride $(POCl_3)$,and hydrogen chloride $(HCl)$. Therefore,all the given options are correct.

When $H_2SO_4$ reacts with $PCl_5$,the obtained product is/are:

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