When $RNA$ is hydrolysed,there is no relationship among the quantities of different bases obtained. What does this fact suggest about the structure of $RNA$?

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(N/A) $DNA$ molecule is double-stranded,in which base pairing occurs according to Chargaff's rules. Adenine $(A)$ always pairs with thymine $(T)$,and cytosine $(C)$ always pairs with guanine $(G)$. Therefore,upon hydrolysis of $DNA$,the amount of $A$ equals $T$,and the amount of $C$ equals $G$.
In contrast,when $RNA$ is hydrolyzed,there is no fixed relationship or equality among the quantities of the different nitrogenous bases obtained. This observation suggests that $RNA$ does not possess a double-stranded structure with complementary base pairing; rather,it is single-stranded.

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Similar Questions

Chargaff's rule states that in an organism

Given below are two statements:
Assertion $(A)$: Hydrolysis of $DNA$ does not form equal number of $A$ and $T$; $G$ and $C$.
Reason $(R)$: In $DNA$,adenine forms hydrogen bonds with thymine and cytosine forms hydrogen bonds with guanine.
The correct answer is:

In the $DNA$ of $E. coli$,the mole ratio of adenine to cytosine is $0.7$. If the number of moles of adenine in the $DNA$ is $350000$,the number of moles of guanine is equal to:

The pyrimidine bases present in $DNA$ are

In $DNA$,the base units are linked by which of the following?

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