When SO_2 is passed through cupric chloride ( | vedclass

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(C) When $SO_2$ is passed through a solution of cupric chloride $(CuCl_2)$,it acts as a reducing agent. The reaction is: $2CuCl_2 + SO_2 + 2H_2O \righ

Vedclass · Accepted Answer

$C$. The solution becomes colourless and a white precipitate of $Cu_2Cl_2$ is obtained

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(C) When $SO_2$ is passed through a solution of cupric chloride $(CuCl_2)$,it acts as a reducing agent. The reaction is: $2CuCl_2 + SO_2 + 2H_2O \rightarrow Cu_2Cl_2 + H_2SO_4 + 2HCl$. In this reaction,$Cu^{2+}$ is reduced to $Cu^+$,resulting in the formation of a white precipitate of cuprous chloride $(Cu_2Cl_2)$. As the blue $Cu^{2+}$ ions are converted to $Cu^+$,the solution loses its blue colour and becomes colourless.

When $SO_2$ is passed through cupric chloride $(CuCl_2)$ solution,what is the observation?

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