When CO_2 is passed into lime water,it turns | vedclass

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(B) When $CO_2$ is passed through lime water,it forms a white precipitate of calcium carbonate: $Ca(OH)_2 + CO_2 \xrightarrow{} CaCO_{3(s)} + H_2O$ Wh

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Water-soluble $Ca(HCO_3)_2$ is formed

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(B) When $CO_2$ is passed through lime water,it forms a white precipitate of calcium carbonate: $Ca(OH)_2 + CO_2 \xrightarrow{} CaCO_{3(s)} + H_2O$ When excess $CO_2$ is passed,the insoluble $CaCO_3$ reacts with $CO_2$ and water to form water-soluble calcium bicarbonate: $CaCO_3 + CO_2 + H_2O \xrightarrow{} Ca(HCO_3)_2$ Thus,the milkiness disappears due to the formation of soluble $Ca(HCO_3)_2$.

List-$I$	List-$II$
$I$. $CaSO_4 \cdot 2H_2O$	$A$. Knee cement
$II$. $CaSO_4 \cdot 0.5H_2O$	$B$. Gypsum
$III$. $CaSO_4$	$C$. Plaster of Paris
	$D$. Dead burnt plaster

When $CO_2$ is passed into lime water,it turns milky. When an excess of $CO_2$ is passed,the milkiness disappears because:

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Match the following:
List-$I$ List-$II$
$I$. $CaSO_4 \cdot 2H_2O$ $A$. Knee cement
$II$. $CaSO_4 \cdot 0.5H_2O$ $B$. Gypsum
$III$. $CaSO_4$ $C$. Plaster of Paris
$D$. Dead burnt plaster

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