When a = -5, b = -6 and c = 10,find the value | vedclass

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(B) We know the algebraic identity: $a^{3} + b^{3} + c^{3} - 3abc = (a + b + c)(a^{2} + b^{2} + c^{2} - ab - bc - ca)$.The denominator is given as $(a

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$1$

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(B) We know the algebraic identity: $a^{3} + b^{3} + c^{3} - 3abc = (a + b + c)(a^{2} + b^{2} + c^{2} - ab - bc - ca)$.The denominator is given as $(ab + bc + ca - a^{2} - b^{2} - c^{2})$,which can be written as $-(a^{2} + b^{2} + c^{2} - ab - bc - ca)$.Substituting these into the expression:$\frac{(a + b + c)(a^{2} + b^{2} + c^{2} - ab - bc - ca)}{-(a^{2} + b^{2} + c^{2} - ab - bc - ca)} = -(a + b + c)$.Given $a = -5, b = -6, c = 10$:$-(a + b + c) = -(-5 - 6 + 10) = -(-1) = 1$.

When $a = -5, b = -6$ and $c = 10$,find the value of $\frac{a^{3} + b^{3} + c^{3} - 3abc}{ab + bc + ca - a^{2} - b^{2} - c^{2}}$.

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