(D) When $SO_{2}$ is passed through an acidified $K_{2}Cr_{2}O_{7}$ solution,the orange dichromate ion $(Cr_{2}O_{7}^{2-})$ is reduced to the green ch

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

green $Cr_{2}(SO_{4})_{3}$ is formed

(D) When $SO_{2}$ is passed through an acidified $K_{2}Cr_{2}O_{7}$ solution,the orange dichromate ion $(Cr_{2}O_{7}^{2-})$ is reduced to the green chromium$(III)$ ion $(Cr^{3+})$.The balanced chemical equation is:$K_{2}Cr_{2}O_{7} + H_{2}SO_{4} + 3SO_{2} \rightarrow K_{2}SO_{4} + Cr_{2}(SO_{4})_{3} + H_{2}O$As a result,the solution turns green due to the formation of $Cr_{2}(SO_{4})_{3}$.

Class 11 Chemistry Redox Reactions Redox reaction and Method for balancing Redox reaction

Medium

When $SO_{2}$ is passed through acidified $K_{2}Cr_{2}O_{7}$,the process that takes place is

MHT CET 2020 All MHT CET

A
the solution turns blue
B
the solution is decolourised
C
$SO_{2}$ is reduced
D
green $Cr_{2}(SO_{4})_{3}$ is formed

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Redox Reactions

Subtopic

Redox reaction and Method for balancing Redox reaction

Previous Year

MHT CET 2020 Paper All MHT CET years →

Assertion: Change in color of acidic solution of potassium dichromate by breath is used to test drunk drivers.
Reason: Change in color is due to the complexation of alcohol with potassium dichromate.

DifficultAIIMS 2006

View Solution

Permanganate ion reacts with bromide ion in basic medium to give manganese dioxide and bromate ion. Write the balanced ionic equation for the reaction.

Medium

View Solution

Assign $A, B, C, D$ from the given type of reaction.
$MnO_2 + 2KOH + \frac{1}{2}O_2 \longrightarrow K_2MnO_4 + H_2O$

Difficult

View Solution

In the balanced chemical reaction,$IO_3^- + a\;I^{-} + b\;H^{+} \to c\;H_2O + d\;I_2$,$a$,$b$,$c$,and $d$ respectively correspond to

DifficultAIIMS 2005

View Solution

Assign $A, B, C, D$ from the given type of reaction.
$Ba(OH)_2 + SO_2 \longrightarrow BaSO_3 \downarrow + H_2O$

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

When $SO_{2}$ is passed through acidified $K_{2}Cr_{2}O_{7}$,the process that takes place is

Similar Questions

Assertion: Change in color of acidic solution of potassium dichromate by breath is used to test drunk drivers.Reason: Change in color is due to the complexation of alcohol with potassium dichromate.

Permanganate ion reacts with bromide ion in basic medium to give manganese dioxide and bromate ion. Write the balanced ionic equation for the reaction.

Assign $A, B, C, D$ from the given type of reaction.$MnO_2 + 2KOH + \frac{1}{2}O_2 \longrightarrow K_2MnO_4 + H_2O$

In the balanced chemical reaction,$IO_3^- + a\;I^{-} + b\;H^{+} \to c\;H_2O + d\;I_2$,$a$,$b$,$c$,and $d$ respectively correspond to

Assign $A, B, C, D$ from the given type of reaction.$Ba(OH)_2 + SO_2 \longrightarrow BaSO_3 \downarrow + H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion: Change in color of acidic solution of potassium dichromate by breath is used to test drunk drivers.
Reason: Change in color is due to the complexation of alcohol with potassium dichromate.

Assign $A, B, C, D$ from the given type of reaction.
$MnO_2 + 2KOH + \frac{1}{2}O_2 \longrightarrow K_2MnO_4 + H_2O$

Assign $A, B, C, D$ from the given type of reaction.
$Ba(OH)_2 + SO_2 \longrightarrow BaSO_3 \downarrow + H_2O$