When AgNO_3 solution is added in excess to 1 | vedclass

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(B) The reaction of $AgNO_3$ with a coordination compound precipitates the chloride ions present outside the coordination sphere as $AgCl$. Since $1 \

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$4$

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(B) The reaction of $AgNO_3$ with a coordination compound precipitates the chloride ions present outside the coordination sphere as $AgCl$. Since $1 \ mole$ of $AgCl$ is formed from $1 \ mole$ of the complex,there must be only $1 \ Cl^-$ ion outside the coordination sphere. The formula of the complex can be written as $[Co(NH_3)_X Cl_2]Cl$. For $Co(III)$,the coordination number is $6$. Therefore,$X + 2 = 6$,which gives $X = 4$.

When $AgNO_3$ solution is added in excess to $1 \ M$ solution of $CoCl_3 \cdot X \ NH_3$,one mole of $AgCl$ is formed. What is the value of '$X$'?

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