When $_{92}U^{235}$ undergoes fission,$0.1\%$ of its original mass is converted into energy. How much energy is released if $1\,kg$ of $_{92}U^{235}$ undergoes fission?

$A$ nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of mass $\frac{M}{4}$ and $\frac{3M}{4}$. If the speed of light is $c$,the speed of the daughter nucleus of mass $\frac{M}{4}$ is:

Consider the nuclear fission reaction ${ }_0^1 n+{ }_{92}^{235} U \longrightarrow{ }_{56}^{144} Ba+{ }_{36}^{89} Kr+3{ }_0^1 n$. Assuming all the kinetic energy is carried away by the fast neutrons only and total binding energies of ${ }_{92}^{235} U, { }_{56}^{144} Ba$ and ${ }_{36}^{89} Kr$ to be $1800 \ MeV, 1200 \ MeV$ and $780 \ MeV$ respectively,the average kinetic energy carried by each fast neutron is (in $MeV$):

Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

Complete the following nuclear reaction:
${ }_{0}^{1} n+{ }_{92}^{235} U \rightarrow{ }_{92}^{236} U \rightarrow$ $\qquad$ $+{ }_{41}^{99} Nb+$ $\qquad$.

Match the $\text{LIST-I}$ with $\text{LIST-II}$:

$A. \text{ } _0^1 n + { }_{92}^{235} U \rightarrow { }_{54}^{140} Xe + { }_{38}^{94} Sr + 2_0^1 n$	$I. \text{ Chemical reaction}$
$B. \text{ } 2H_2 + O_2 \rightarrow 2H_2O$	$II. \text{ Fusion with } +ve \ Q \text{ value}$
$C. \text{ } _1^2 H + _1^2 H \rightarrow _2^3 He + _0^1 n$	$III. \text{ Fission}$
$D. \text{ } _1^1 H + _1^3 H \rightarrow _1^2 H + _1^2 H$	$IV. \text{ Fusion with } -ve \ Q \text{ value}$

Choose the correct answer from the options given below: