When Cl_2 gas reacts with hot and concentrate | vedclass

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(B) The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is:$3Cl_2 + 6NaOH \rightarrow NaClO_3 + 5NaCl + 3H_2O$In $Cl_2$,t

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$0$ to $-1$ and $0$ to $+5$

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(B) The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is:$3Cl_2 + 6NaOH ightarrow NaClO_3 + 5NaCl + 3H_2O$In $Cl_2$,the oxidation number of $Cl$ is $0$.In $NaCl$,the oxidation number of $Cl$ is $-1$.In $NaClO_3$,the oxidation number of $Cl$ is $x + (-2 	imes 3) = -1 \Rightarrow x = +5$.Thus,the oxidation number changes from $0$ to $-1$ and $0$ to $+5$.

When $Cl_2$ gas reacts with hot and concentrated sodium hydroxide solution,the oxidation number of chlorine changes from

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