When 100, V DC is applied across a solenoid,a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For $DC$ supply,the solenoid acts as a pure resistor $R$. Given $V = 100\, V$ and $I = 1\, A$,the resistance is $R = \frac{V}{I} = \frac{100}{1} =

Vedclass · Accepted Answer

$200\, \Omega, 0.55\, H$

Vedclass · Answer

(D) For $DC$ supply,the solenoid acts as a pure resistor $R$. Given $V = 100\, V$ and $I = 1\, A$,the resistance is $R = \frac{V}{I} = \frac{100}{1} = 100\, \Omega$.For $AC$ supply,the impedance $Z$ is given by $Z = \frac{V_{rms}}{I_{rms}} = \frac{100}{0.5} = 200\, \Omega$.The impedance of an $RL$ circuit is $Z = \sqrt{R^2 + X_L^2}$,where $X_L = 2\pi f L$.Substituting the values: $200 = \sqrt{100^2 + (2 \cdot \pi \cdot 50 \cdot L)^2}$.Squaring both sides: $200^2 = 100^2 + (100\pi L)^2$.$40000 = 10000 + (100\pi L)^2$.$30000 = (100\pi L)^2$.Taking the square root: $100\pi L = \sqrt{30000} = 100\sqrt{3} \approx 173.2$.$L = \frac{173.2}{100\pi} \approx \frac{1.732}{3.14} \approx 0.55\, H$.Thus,the impedance is $200\, \Omega$ and the inductance is $0.55\, H$.

When $100\, V$ $DC$ is applied across a solenoid,a current of $1\, A$ flows in it. When $100\, V$ $AC$ is applied across the same coil,the current drops to $0.5\, A$. If the frequency of the $AC$ source is $50\, Hz$,the impedance and inductance of the solenoid are:

Similar Questions

An inductance coil has a resistance of $80 \Omega$. When an $AC$ signal of frequency $480 \text{ Hz}$ is applied to the coil,the voltage leads the current by $45^{\circ}$. The inductance of the coil in henry is $\left[\sin 45^{\circ}=\cos 45^{\circ}=1 / \sqrt{2}\right]$

The value of alternating emf $E$ in the given circuit will be......$V$.

An a.c. source of frequency $f$ is connected to a circuit containing an inductance $L$ and resistance $R$ in series. The impedance of this circuit is

$A$ coil having an inductance of $\frac{1}{\pi} \text{ H}$ is connected in series with a resistance of $300 \text{ } \Omega$. If $20 \text{ V}$ from a $200 \text{ Hz}$ source are impressed across the combination,the value of the phase angle between the voltage and the current is

In an $LR$-circuit,the inductive reactance is equal to the resistance $R$ of the circuit. An e.m.f. $E = E_0 \cos(\omega t)$ is applied to the circuit. The power consumed in the circuit is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module