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(D) The heat of neutralization for a strong acid and strong base is $\Delta H = -13.5 \ kcal/eq$. For $H_2A$ (a weak acid) with a strong base: $H_2A +

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$-19$

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(D) The heat of neutralization for a strong acid and strong base is $\Delta H = -13.5 \ kcal/eq$. For $H_2A$ (a weak acid) with a strong base: $H_2A + 2OH^- ightarrow A^{2-} + 2H_2O$,$\Delta H = 2 	imes (-13) = -26 \ kcal$. For $B(OH)_2$ (a weak base) with a strong acid: $B(OH)_2 + 2H^+ ightarrow B^{2+} + 2H_2O$,$\Delta H = 2 	imes (-10) = -20 \ kcal$. We want the enthalpy for: $H_2A + B(OH)_2 ightarrow BA + 2H_2O$. Using Hess's Law: $(H_2A + 2OH^-$ $ightarrow A^{2-} + 2H_2O) + (B(OH)_2 + 2H^+$ $ightarrow B^{2+} + 2H_2O) - (2H^+ + 2OH^-$ $ightarrow 2H_2O)$. $\Delta H = (-26) + (-20) - (2 	imes -13.5) = -46 + 27 = -19 \ kcal$.

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