When a capacitor is connected in a series $LR$ circuit,what happens to the alternating current flowing in the circuit?

In a series $LCR$ circuit, the voltages across $L, C$, and $R$ are $50 \,V, 20 \,V$, and $40 \,V$ respectively. The $A.C.$ voltage applied across the combination of $LCR$ is: (in $\,V$)

In the circuit shown in the figure,the $AC$ source provides a voltage $V = 20 \cos(2000t)$. Neglecting source resistance,the voltmeter and ammeter readings will be:

In an $L-C-R$ circuit,the capacitance is changed from $C$ to $4 C$. For the same resonant frequency,the inductance should be changed from $L$ to

An inductor $20 \, mH$,a capacitor $50 \, \mu F$ and a resistor $40 \, \Omega$ are connected in series across a source of emf $V = 10 \, \sin \, 340t$. The power loss in the $A.C.$ circuit is ...... $W$.

$A$ circuit has three elements: a resistance of $11 \Omega$,a coil of inductive reactance $120 \Omega$,and a capacitive reactance of $120 \Omega$ in series,connected to an $A.C.$ source of $110 \, V, 60 \, Hz$. Which of the three elements has the minimum potential difference?